The reaction CH_3CONH_2 xrightarrow{NaOBr} gi | vedclass

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Question

(D) The reaction $CH_3CONH_2 \xrightarrow{NaOBr} CH_3NH_2$ is known as the $Hofmann$ bromamide degradation reaction.In this reaction,an amide is treat

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$CH_3NH_2$

Vedclass · Answer

(D) The reaction $CH_3CONH_2 \xrightarrow{NaOBr} CH_3NH_2$ is known as the $Hofmann$ bromamide degradation reaction.In this reaction,an amide is treated with an aqueous or ethanolic solution of $NaOH$ and $Br_2$ to produce a primary amine with one carbon atom less than the original amide.Therefore,$CH_3CONH_2$ (acetamide) yields $CH_3NH_2$ (methanamine).

The reaction $CH_3CONH_2 \xrightarrow{NaOBr}$ gives:

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